4.9t^2-3t-195=0

Solution for 4.9t^2-3t-195=0 equation:

4.9t^2-3t-195=0

a = 4.9; b = -3; c = -195;
Δ = b2-4ac
Δ = -32-4·4.9·(-195)
Δ = 3831
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3831}=\sqrt{1*3831}=\sqrt{1}*\sqrt{3831}=1\sqrt{3831}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-1\sqrt{3831}}{2*4.9}=\frac{3-1\sqrt{3831}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+1\sqrt{3831}}{2*4.9}=\frac{3+1\sqrt{3831}}{9.8}
$